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Introductory And Intermediate Algebra Through Applications 3 Chapter 7
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March 12, 2025
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Chapter 6
Exercises
an integer that is a factor of each integer.
monomials is the product
of the greatest
common factor of the coefficients and, for
each variable, the variable to the lowest
mono
mials
.
5
GCF
y
yyyyy
y
=
⋅⋅⋅⋅
=
10.
4
33
55
GCF
aa
a
a
a
a
=⋅⋅⋅⋅
=
12.
3
2
93
3
GCF
3
3
m
mmm
mm
m
=
⋅
⋅⋅⋅
=⋅
⋅
=
2
3
2
22222
GCF
2
2
2
8
mn
m
n
n
mn
m
n
=
⋅⋅⋅⋅⋅
⋅⋅
=
⋅⋅⋅
⋅
=
()
()
GCF
5
2
n
=+
18.
()()
()
44
GCF
4
yy
y
y
yy
−=
⋅−
=−
()
(
)
()
()
()
2
65
1
y
=−
()
(
)
()
82
rt
=−
()
()
()
36
bb
=−
()
23
()
34.
()
(
)
32
23
22
22
35
3
5
pq
pq
pq
p
pq
q
+=
+
()
(
)
()
15
3
cd
c
d
=−
()
()
()
()
()
(
)
23
2
()
()
2
33
9
xx
x
=−
−
()
()
22
96
cc
c
=+
+
Chapter 6 Factoring Polynom
ials
108
48.
()
()
()
()
33
2
12
9
15
34
3
5
mm
m
=+
+
()
(
)
(
)
()
53
2
mn
m
n
=−
+
52.
()
(
)
(
)
24
3
3
322
18
24
30
xy
x
y
xy
−+
()
()
()
()
()
()
()
(
)
()
()
()
(
)
()
(
)
11
2
nm
=−
−
()
(
)
()
()
()
()
()
(
)
()
()
()
()
()
(
)
22
3
xy
=−
−
()
()
()
()
()
()
52
ab
=−
−
()
()
()
(
)
265
bcac
=+
−
80.
()
()
1
1
11
Sa
N
d
d
Sa
d
N
dN
Sa
NN
Sa
=+
−
−=
−
−
−
=
−−
−
()
1
n
ar
S
S
+
(
)
()
(
)
()
()
(
)
()
2
74
mm
=−
22
1
12
12
12
1
bb
bb
++
()
(
)
423
cab
a
=+
−
GCF
7
x
=
Section 6.2 Factoring T
rinomials Whose Leading Co
efficient Is 1
109
()
()
()
()
2
Hx
y
xy
xy
xy
+
=
++
b.
Reversing the order of the dig
its so
that
a
is the digit in the thousands
place,
c
is the digit in the tens place
()
()
()
(
)
()
1000
100
10
9
111
10
10
111
ab
c
d
dc
b
a
++
+
=+
−
−
Since 9 is a factor of
each term of
sion is divisible by 9.
(
)
b.
2
16
,
48,
xx
y
−−
Coefficient Is 1
Exercises
written in descending
order.
4.
If each term in a trinomial has a common
()
()
()
()
(
)
Prime polynomial
()
(
)
()
(
)
()
()
Chapter 6 Factoring Polynom
ials
110
()
(
)
()
(
)
71
2
xx
=−
+
−
()
(
)
()
(
)
89
yy
=−
−
()
()
()
()
()
42
5
yy
=−
+
()
()
(
)
21
4
xx
=−−
()
2
52
3
zz
=−
−
()
(
)
17
xx
x
=+
−
()
67
qq
q
=+
−
()
()
()
()
()
32
4
yy
y
=−
−
()
2
53
2
bb
b
=+
+
()
()
()
()
(
)
()
()
2
49
by
y
y
=+
−
()
()
(
)
()
()
()
()
()
Section 6.3 Factoring T
rinomials Whose Leading Co
efficient is Not 1
111
()
()
()
()
()
()
(
)
18
18
xx
⎜⎟
⎝⎠
=−
−
+
⎜⎟
⎝⎠
()
(
)
()
43
1
xx
x
−+
−
()
()
2
x
−
()
2
3
x
x
−
=
−
Whose Leading
Exercises
()
28.
()
(
)
49
2
4
1
2
nn
n
n
−+
=
−
−
()
(
)
52
32
nn
=+
+
()
(
)
31
5
xx
=−
−
()
()
(
)
51
3
bb
=−
−
+
112
()
()
()
()
()
(
)
32
1
7
xx
x
=+
+
()
()
(
)
2
521
3
nn
n
=−
−
()
()
(
)
31
3
xy
y
y
=+
+
()
()
(
)
22
3
4
st
s
t
=−+
()
(
)
(
)
42
3
2
3
ab
a
b
=−
−
()
()
74.
()
2
24
6
18
xy
xy
x
y
−−
+
()
()
()
(
)
45
2
1
xx
=+
−
()
()
(
)
523
31
ab
a
a
=−
−
()
()
(
)
32
4
5
aab
a
b
=−
+
()
92. a.
()
24
rr
r
r
ππ
−=
−
()
2
32
23
1
23
6
nn
n
nn
n
++
++
=
a.
7;
11
c.
2;
4
−−
3.
Answers
may
vary.
Trinomials, the
Difference
or Difference of Cubes
Exercises
square, because the middle term is not twice
the
product
of
a
and 5
b.
perfect
squares.
22.
Neither
()
()
()
()
()
()
()
()
()
()
2
12
1
y
=+
()
()
2
2
()
()
()
()
()
()
114
()
()
()
()
()
()
55
5
mm
m
=+
−
()
()
()
3
31
0
1
0
tt
t
=+−
()
()
()
()
()
()
()
()
()
()
()
()
()
22
()
()
()
(
)
11
aby
y
=−
+
−
()
()
()
()
()
()
()
()
22
2
22
2
22
4
tt
t
tt
t
=−
+
⋅
+
=−
++
()
()
22
aba
a
bb
=−
++
()
()
()
()
22
33
3
33
9
xx
x
xx
x
=+
−
⋅
+
=+
−+
()
()
(
)
()
()
(
)
2
22
2
2
22
2
24
2
xx
x
xx
x
=−
+
⋅+
=−
+
+
()
()
()
2
32
2
4
xx
x
=−
+
+
()
()
()
32
24
1
6
4
nn
n
n
=+
−
+
()
()
()
32
24
2
xx
x
x
=+
−
+
()
()
()
()
()
()
()
()
2
33
9
mm
m
=−
++
()
()
()
45
2
5
2
tt
=+
−
Section 6.5 Solving Quadrat
ic Equations by Factoring
115
()
()
2
16,000
1
2
16,000
1
rr
r
=+
+
=+
()
()
()
21
22
212
2
11
3
4
rr
r
r
r
r
π
=−
+
⋅
+
2. a.
x
2
d.
33
xx
−−
g.
()
large outer square can also be represented by
the sum of the areas of the smaller interior
rectangles and squares. The area of the blue
square
is
2
,
a
the area of each green rectangle
22
2.
aa
b
b
=+
+
Equations
by
Factoring
Exercises
equals to the square of the hypotenuse.
()
23
0
23
t
t
+=
=−
16.
()
25
4
0
yy
−=
20
y
=
or
54
0
y
−=
18.
()
(
)
33
1
0
tt
−−
=
45
5
4
x
x
−=
−
=
45
5
4
x
x
=−
=−
22.
()
12
0
tt
+=
116
()
()
30
0
t
t
=
=
or
12
0
21
1
2
t
t
t
+=
=−
=−
10
1
x
x
−=
=
or
20
2
x
x
+=
=−
2
90
0
()
(
)
23
40
yy
−+
=
23
0
23
3
y
y
−=
=
or
40
4
y
y
+=
=−
()
(
)
21
0
21
t
t
−=
=
or
23
0
23
t
t
−=
=
36.
2
02
5
1
0
1
yy
=+
+
5
()
()
70
t
+=
or
70
t
−=
41
0
x
+=
()
()
()
2
92
1
0
91
1
0
tt
tt
++
=
++
=
10
1
t
t
+=
=−
()
()
(
)
23
1
5
0
nn
−−
=
31
0
31
n
n
−=
=
or
50
5
n
n
−=
=
46.
()
()
31
0
rr
+=
20
2
r
r
−=
=
or
50
5
r
r
+=
=−
3
y
=−
4
y
=
50.
()
()
2
31
8
tt
−=
30
t
+=
or
60
t
−=
52.
()
(
)
31
7
1
0
kk
+=
−
32
0
3
k
k
+=
=−
or
50
k
+=
117
54.
()
()
(
)
12
33
9
34
1
3
0
xx
xx
+=
−+
=
41
0
x
−=
or
30
x
+=
56.
()
2
36
mm
=
30
0
m
m
=
=
or
20
2
m
m
−=
=
()
()
2
91
6
0
34
340
y
yy
−=
+−
=
34
0
34
y
y
+=
=−
or
34
0
34
y
y
−=
=
60.
()
()
()
2
12
48
22
0
x
xx
=
+−
=
()
()
64.
()
31
0
rr
+=
2
r
=
5
r
=−
(
)
()
()
(
)
2
27
1
2
0
23
4
0
nn
nn
++
=
++
=
()
(
)
()
(
)
2
561
0
14
0
mm
mm
−−
=
−
−−
=
10
1
m
m
−=
=
or
40
4
m
m
−=
=
()
(
)
()
()
2
2
31
0
1
8
32
8
0
47
0
tt
tt
tt
−−
=
−−
=
+−
=
()
(
)
()
(
)
2
32
5
1
6
31
5
0
xx
x
xx
+−
=
+−
=
31
0
x
+=
or
50
x
−=
()
()
(
)
83
6
02
1
4
nn
n
nn
+=
−
=+−
()
()
03
1
13
u
u
=+
−=
118
78.
()
()
32
8
47
0
nn
nn
+=
−+
=
80.
()
92
7
bb
=
2
44
5
0
xx
−−=
73
0
m
−=
or
73
0
m
+=
2
650
nn
−=
90.
222
2
12
13
25
0
x
x
+=
−=
92.
()
()
(
)
16
8
24
0
82
3
1
0
tt
tt
−+
+
=
−−+
=
2
or 1.5 sec.
()
(
)
1
.
a.
Possible answer:
2
56
0
xx
−+
=
()
()
(
)
20
2
x
x
+=
=−
or
50
5
x
x
−=
=
()
(
)
3.
The
zero-product property is true for more