of 1
Solution 6.149
For air take
=1.2 kg/m3 and
= 0.000015 kg/ms. With no elevation change and negligible
tank velocity, the energy equation would yield
2
tank 1 , 0.5 and 0.7
2
atm entrance nozzle ent noz
VL
p p f K K K K
D

= + + +


Since p is given, we can use this expression plus the Moody chart to predict V and Q = AV and
compare with the flow-nozzle measurements. The flow nozzle formula is:
2where ( ) , from Fig. 6.42 and 0.5
mano
p
The friction factor is given by the smooth-pipe Moody formula, Eq. (6.48) for
= 0. The results