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Fluid Mechanics 8 Chapter 6
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November 20, 2024
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Solution 6.149
For air take
=
1.2 kg/m
3
and
=
0.000015 kg/m
s. With no elevation change and negligible
tank velocity, the energy equation would yield
2
tank
1
,
0.5
and
0.7
2
atm
entrance
nozzle
ent
noz
VL
p
p
f
K
K
K
K
D
−
=
+
+
+
Since
p
is given, we can use this expression plus the Moody chart to predict
V
and
Q
=
AV
and
compare with the flow-nozzle measurements. The flow nozzle formula is:
2
wher
e
(
)
,
from
Fig
. 6.42
and
0.5
mano
p
−
The friction factor is given by the smooth-pipe Moody formula, Eq. (6.48) for
=
0. The results