Solution 10.84
First get the conditions at “2” by assuming a frictionless acceleration:
Fig. P10.84
22
2
12
1 1 2 2 1 1 2 2
VV
(2)
E y 10 10.062 ft E y , Also, V y V y 20
2g 2(32.2) 2g
= + = + = = = + = =
2 2 2 24.4
Solve for V 24.4 ft/s; y . (a) Fr 4.75
32.2(0.820)
Ans = 0.820 ft
2
323
2
y1
Jump: 1 8Fr 1 6.23, y (b)
y2 Ans.
= + −
5.11 ft
33
32
2f
23
(y y ) (5.11 0.82)
E 10.062 ft; h 4.71 ft,
4y y 4(0.82)(5.11)
4.71
Dissipation (c)
10.06 Ans.
−−
= = =
=47%